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2012
P1 Q3
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Sigma Notation
12 P1 Q3
2012 H2 Mathematics Paper 1 Question 3
Sigma Notation
Answers
(i)
u
2
=
5
6
,
u
3
=
1
4
{u_2 = \frac{5}{6}, \; u_3 = \frac{1}{4}}
u
2
=
6
5
,
u
3
=
4
1
(ii)
Out of syllabus
(iii)
Out of syllabus
Full solutions
(i)
u
2
=
3
u
1
−
1
6
=
3
(
2
)
−
1
6
=
5
6
■
\begin{align*} u_2 &= \frac{3u_1 - 1}{6} \\ &= \frac{3(2) - 1}{6} \\ &= \frac{5}{6} \; \blacksquare \end{align*}
u
2
=
6
3
u
1
−
1
=
6
3
(
2
)
−
1
=
6
5
■
u
3
=
3
u
2
−
1
6
=
3
(
5
6
)
−
1
6
=
1
4
■
\begin{align*} u_3 &= \frac{3u_2 - 1}{6} \\ &= \frac{3(\frac{5}{6}) - 1}{6} \\ &= \frac{1}{4} \; \blacksquare \end{align*}
u
3
=
6
3
u
2
−
1
=
6
3
(
6
5
)
−
1
=
4
1
■
(ii)
Out of syllabus
(iii)
Out of syllabus
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