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P2 Q2
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19 P2 Q2
2019 H2 Mathematics Paper 2 Question 2
Graphs and Transformations
Answers
(i)
x
=
−
8
3
{x=- \frac{8}{3}}
x
=
−
3
8
x
=
1
{x=1}
x
=
1
y
=
0
{y=0}
y
=
0
(
0
,
−
1
4
)
,
(
2
,
0
)
{\left(0, -\frac{1}{4}\right), \left(2,0\right)}
(
0
,
−
4
1
)
,
(
2
,
0
)
(ii)
x
<
−
8
3
{x<- \frac{8}{3}}
x
<
−
3
8
or
1
<
x
<
2
{1 < x < 2}
1
<
x
<
2
(iii)
−
8
3
<
x
<
1
{- \frac{8}{3}<x<1}
−
3
8
<
x
<
1
or
x
>
2
{x > 2}
x
>
2
Full solutions
(i)
2
−
x
3
x
2
+
5
x
−
8
=
2
−
x
(
3
x
+
8
)
(
x
−
1
)
\frac{2 - x}{3 x^2 + 5 x - 8} = \frac{2 - x}{(3 x + 8)(x - 1)}
3
x
2
+
5
x
−
8
2
−
x
=
(
3
x
+
8
)
(
x
−
1
)
2
−
x
(ii)
From the graph, solution of the inequality:
x
<
−
8
3
or
1
<
x
<
2
■
x<- \frac{8}{3} \; \textrm{ or } \; 1 < x < 2 \; \blacksquare
x
<
−
3
8
or
1
<
x
<
2
■
(iii)
x
−
2
3
x
2
+
5
x
−
8
>
0
2
−
x
3
x
2
+
5
x
−
8
<
0
\begin{align*} \frac{x-2}{3 x^2 + 5 x - 8} &> 0 \\ \frac{2-x}{3 x^2 + 5 x - 8} &< 0 \end{align*}
3
x
2
+
5
x
−
8
x
−
2
3
x
2
+
5
x
−
8
2
−
x
>
0
<
0
From the graph, solution of the inequality:
−
8
3
<
x
<
1
or
x
>
2
■
- \frac{8}{3}<x<1 \; \textrm{ or } \; x > 2 \; \blacksquare
−
3
8
<
x
<
1
or
x
>
2
■
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