2010 H2 Mathematics Paper 2 Question 10

Linear Correlation and Regression

Answers

(iia)
0.9860{0.9860}
(iib)
0.9907{0.9907}
F=c+dv2{F = c + d v^2} is a better model.
From part (i), the scatter diagram suggests that, as v{v} increases, F{F} increases at an increasing rate, which is more consistent with a quadratic model rather than a linear model.
From part (ii), the product moment correlation coefficient between v2{v^2} and F{F} is also closer to 1,{1,} indicating a stronger linear correlation between v2{v^2} and F{F} compared to between v{v} and F{F}.
F=3.20+0.0242v2{F = 3.20+0.0242v^2}
F=30.7{F=30.7}
Neither the regression line of v{v} on F{F} nor the regression line of v2{v^2} on F{F} should be used because v{v} is the independent variable in this scenario.

Full solutions

(i)

(iia)
Using a GC, product moment correlation between v{v} and F:{F:}
r1=0.9860 (4 dp)  r_1 = 0.9860 \textrm{ (4 dp)} \; \blacksquare
(iib)
Product moment correlation between v2{v^2} and F:{F:}
r2=0.9907 (4 dp)  r_2 = 0.9907 \textrm{ (4 dp)} \; \blacksquare

(iii)

F=c+dv2{F = c + d v^2} is a better model. {\blacksquare}
From part (i), the scatter diagram suggests that, as v{v} increases, F{F} increases at an increasing rate, which is more consistent with a quadratic model rather than a linear model.
From part (ii), the product moment correlation coefficient between v2{v^2} and F{F} is also closer to 1,{1,} indicating a stronger linear correlation between v2{v^2} and F{F} compared to between v{v} and F{F}.

(iv)

Using a GC, least squares regression line of F{F} on v2:{v^2:}
F=3.1957+0.024242v2F=3.20+0.0242v2 (3 sf)  \begin{align*} & F = 3.1957+0.024242v^2 \\ & F = 3.20+0.0242v^2 \textrm{ (3 sf)} \; \blacksquare \end{align*}
When F=26.0,{F=26.0,}
26.0=3.1957+0.024242v2v2=940.70v=30.7 (3 sf)  \begin{align*} 26.0 &= 3.1957 + 0.024242 v^2 \\ v^2 &= 940.70 \\ v &= 30.7 \textrm{ (3 sf)} \; \blacksquare \end{align*}
Neither the regression line of v{v} on F{F} nor the regression line of v2{v^2} on F{F} should be used because v{v} is the independent variable in this scenario. {\blacksquare}