2023 H2 Mathematics Paper 2 Question 7

Linear Correlation and Regression

Answers

(ai)
0.9281.{{0.9281.}}
(aii)
0.9697.{{0.9697.}}
ey=cx+d{{ \mathrm{e}^y = cx + d}} gives a better fit to the data because the r{{|r|}} value is closer to 1.{{1.}}
ey=376x1880.{{\mathrm{e}^y = 376x -1880.}}
8.87{{8.87}} million.
The estimate is not reliable as x=24{{x=24}} lies outside the given data range 4x18.{{ 4 \leq x \leq 18.}}

Full solutions

(ai)
0.9281  (4 dp)  {{0.9281 \; \textrm{(4 dp)} \; \blacksquare}}
(aii)
0.9697  (4 dp)  {{0.9697 \; \textrm{(4 dp)} \; \blacksquare}}

(b)

ey=cx+d{{ \mathrm{e}^y = cx + d}} gives a better fit to the data because the r{{|r|}} value is closer to 1  {{1 \; \blacksquare}}

From the GC, equation of the regression line is

ey=1881.5+375.62xey=376x1880  \begin{gather*} \mathrm{e}^y = -1881.5+375.62x \\ \mathrm{e}^y = 376x -1880 \; \blacksquare \end{gather*}

(c)

In 2024,x=24{{2024, x=24}}

ey=375.62(24)1881.5=7133.3y=ln7133.3=8.87\begin{align*} \mathrm{e}^y &= 375.62(24) -1881.5 \\ &= 7133.3 \\ y &= \ln 7133.3 \\ &= 8.87 \end{align*}

Hence the number of mobile phone subscriptions in 2024is{{2024 is}} estimated to be 8.87{{8.87 }} million   {{\; \blacksquare}}

The estimate is not reliable as x=24{{x=24}} lies outside the given data range 4x18  {{ 4 \leq x \leq 18 \; \blacksquare}}

Question Commentary

After the unexpectedly theoretical question last year (2022 P2Q10), we are back to a much more standard question on linear regression.

The common techniques of linearisation, GC skills and reliability of estimates will hopefully feel familiar to past practice.